Python Tkinter Button Action

Question

I have this code:

#!/usr/bin/python

import Tkinter
from tkFileDialog import askopenfilename
import tkMessageBox

root = Tkinter.Tk()

def getFileName():
  # show an "Open" dialog box.
  filename = askopenfilename(filetypes = [('Text files', '*.txt'),('All files','*')])

btnIco = Tkinter.Button(root, text="Icon", command=getFileName())
btnIco.pack()

root.mainloop()

What I intended to do was to run the function getFileName when the button is clicked. But instead the function runs when the code is run and the button does not do anything when clicked. Can you please point out what is wrong?

See also stackoverflow.com/q/23936127/3001761

jonrsharpe
– jonrsharpe

2014-06-06 09:44:05 +00:00
Commented Jun 6, 2014 at 9:44 — jonrsharpe
– jonrsharpe, Commented Jun 6, 2014 at 9:44

falsetru · Accepted Answer · 2014-06-06 09:35:40Z

2

Replace the following line:

btnIco = Tkinter.Button(root, text="Icon", command=getFileName())

with:

btnIco = Tkinter.Button(root, text="Icon", command=getFileName)

In other word, remove () after getFileName. By appending (), the code is call getFileName before creating the button, and use the return value of the function as a callback instead of the function itself.

answered Jun 6, 2014 at 9:35

falsetru

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