I have the following node in an XML-document:
<state>
<soso value="3"/>
<good value="1"/>
<bad value="2"/>
<unknown value="0"/>
</state>
I need to sort its elements according to the value attribute's value, so that the result is the following:
<state>
<unknown value="0"/>
<good value="1"/>
<bad value="2"/>
<soso value="3"/>
</state>
How would one do it in python using libxml2?
You can sort the children of a state tag using lxml this way:
from lxml import etree
data = """
<state>
<soso value="3"/>
<good value="1"/>
<bad value="2"/>
<unknown value="0"/>
</state>
"""
state = etree.fromstring(data)
state[:] = sorted(state, key=lambda x: int(x.attrib.get('value')))
print etree.tostring(state)
Prints:
<state>
<unknown value="0"/>
<good value="1"/>
<bad value="2"/>
<soso value="3"/>
</state>
Note that it really sounds like applying an XSLT transformation is more logical and simple here, see:
See also:
