Parsing JSON with multiple tuples to List<object> in scala

Question

[
{"fname":"Foo","lname":"Pacman"},
{"fname":"Bar","lname":"Mario"},
{"fname":"Poo","lname":"Wario"}
]

Well I have JSON string in this format, Now what I need is to convert each tuples -> {"fname":"Foo","lname":"Pacman"}

To a Person object, for e.g. lets assume I have a case class

case class Person(fname:String,lname:String)

Now how am I to get, List<person>

If I had a JSON containing data for single tuple, then I could,

val o:Person = parse[Person](jsonString)// I am actually using Jerkson Lib

But since there are more than one tuples, how am i to parse them individually and create objects and create a list.

Ya tried that just now and it works.... Funny , was a 1 line answer val parsedList = parse[List[Person]](jsonString) — mane
– mane, Commented Jun 10, 2014 at 11:22
given the minor syntax error at hand, consider deleting the question. — maasg
– maasg, Commented Jun 10, 2014 at 11:29
Ok, I will but dont you think some one might find it handy?? Like, how much time I looked around the web for this answer. — mane
– mane, Commented Jun 10, 2014 at 11:32
Then it should have a proper answer. @cmbaxter, would you put your solution as an answer? — maasg
– maasg, Commented Jun 10, 2014 at 11:53

cmbaxter · Accepted Answer · 2014-06-10 12:44:17Z

2

Jerkson supports deserializing lists of objects out of the box, so all you should need to do is:

val people = parse[List[Person]](personJson)

answered Jun 10, 2014 at 12:44

cmbaxter

35.5k4 gold badges88 silver badges95 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Ashalynd · Accepted Answer · 2014-06-10 12:52:32Z

2

You can use json4s (which is a wrapper around either jackson or lift-json) where you also get such parsing capabilities out of the box.

   import org.json4s._
   import org.json4s.jackson.JsonMethods._
   implicit val formats = DefaultFormats 

    val personJson = """
      [
      {"fname":"Foo","lname":"Pacman"},
      {"fname":"Bar","lname":"Mario"},
      {"fname":"Poo","lname":"Wario"}
      ]"""
    case class Person(fname:String,lname:String)
    val people = parse(personJson).extract[List[Person]]

answered Jun 10, 2014 at 12:52

Ashalynd

12.6k2 gold badges36 silver badges38 bronze badges

2 Comments

mane Over a year ago

umm, will give json4s a try too for my next projects, since Jerkson doesn't seem to be actively developed, thanks for the answer

Ashalynd Over a year ago

I am using it myself now, seems to be fine. success with your projects :)

Collectives™ on Stack Overflow

Parsing JSON with multiple tuples to List<object> in scala

2 Answers 2

Comments

2 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

2 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related