How to build complex django query as a string

Question

I am dynamically generating a query string with multiple parameters. I am trying to include the object names ('nut', 'jam') in my string. The query has to be an "OR" query. My code is below and I get the error shown below. The solutions here, here, and here did not work for me.

from viewer.models import Model1
from django.db.models import Q
list1 = [
    {'nut' : 'peanut', 'jam' : 'blueberry'},
    {'nut' : 'almond', 'jam' : 'strawberry'}
]
query_string = ""
for x in list1:
    if len(query_string) == 0:
        query_string = "Q(nut='%s', jam='%s')" % (x["nut"], x["jam"])
    else:
        query_string = "%s | Q(nut='%s', jam='%s')" % (query_string, x["nut"], x["jam"])
print query_string # correctly prints Q(nut='peanut', jam='blueberry') | Q(nut='almond', jam='strawberry')
query_results = Model1.objects.filter(query_string)

Error: 
#truncated
File "/Library/Python/2.7/site-packages/Django-1.5.4-py2.7.egg/django/db/models/manager.py", line 155, in filter
    return self.get_query_set().filter(*args, **kwargs)
  File "/Library/Python/2.7/site-packages/Django-1.5.4-py2.7.egg/django/db/models/query.py", line 669, in filter
    return self._filter_or_exclude(False, *args, **kwargs)
  File "/Library/Python/2.7/site-packages/Django-1.5.4-py2.7.egg/django/db/models/query.py", line 687, in _filter_or_exclude
    clone.query.add_q(Q(*args, **kwargs))
  File "/Library/Python/2.7/site-packages/Django-1.5.4-py2.7.egg/django/db/models/sql/query.py", line 1271, in add_q
can_reuse=used_aliases, force_having=force_having)
  File "/Library/Python/2.7/site-packages/Django-1.5.4-py2.7.egg/django/db/models/sql/query.py", line 1066, in add_filter
arg, value = filter_expr
ValueError: too many values to unpack

alecxe · Accepted Answer · 2014-06-10 13:36:08Z

4

Construct a Q object and use it in filter():

from viewer.models import Model1
from django.db.models import Q

list1 = [
    {'nut' : 'peanut', 'jam' : 'blueberry'},
    {'nut' : 'almond', 'jam' : 'strawberry'}
]

q = Q()
for x in list1:
    q.add(Q(**x), Q.OR)

query_results = Model1.objects.filter(q)

Or, you can use operator.or_ to join the list of Q objects:

import operator
from viewer.models import Model1
from django.db.models import Q

list1 = [
    {'nut' : 'peanut', 'jam' : 'blueberry'},
    {'nut' : 'almond', 'jam' : 'strawberry'}
]

query_results = Model1.objects.filter(reduce(operator.or_, 
                                             [Q(**x) for x in list1]))

edited Jun 10, 2014 at 13:36

answered Jun 10, 2014 at 13:25

alecxe

476k127 gold badges1.1k silver badges1.2k bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

How to build complex django query as a string

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related