I want to search a string and see if it contains any of the following words: AB|AG|AS|Ltd|KB|University
I have this working in javascript:
var str = 'Hello test AB';
var forbiddenwords= new RegExp("AB|AG|AS|Ltd|KB|University", "g");
var matchForbidden = str.match(forbiddenwords);
if (matchForbidden !== null) {
console.log("Contains the word");
} else {
console.log("Does not contain the word");
}
How could I make the above work in python?
import re
strg = "Hello test AB"
#str is reserved in python, so it's better to change the variable name
forbiddenwords = re.compile('AB|AG|AS|Ltd|KB|University')
#this is the equivalent of new RegExp('AB|AG|AS|Ltd|KB|University'),
#returns a RegexObject object
if forbiddenwords.search(strg): print 'Contains the word'
#search returns a list of results; if the list is not empty
#(and therefore evaluates to true), then the string contains some of the words
else: print 'Does not contain the word'
#if the list is empty (evaluates to false), string doesn't contain any of the words
You can use re module. Please try below code:
import re
exp = re.compile('AB|AG|AS|Ltd|KB|University')
search_str = "Hello test AB"
if re.search(exp, search_str):
print "Contains the word"
else:
print "Does not contain the word"
str="Hello test AB"
to_match=["AB","AG","AS","Ltd","KB","University"]
for each_to_match in to_match:
if each_to_match in str:
print "Contains"
break
else:
print "doesnt contain"
You can use findall to find all matched words:
import re
s= 'Hello Ltd test AB ';
find_result = re.findall(r'AB|AG|AS|Ltd|KB|University', s)
if not find_result:
print('No words found')
else:
print('Words found are:', find_result)
# The result for given example s is
# Words found are: ['Ltd', 'AB']
If no word is found, that re.findall returns empty list. Also its better not to use str as a name of veritable, since its overwriting build in function in python under the same name.
if re.findall(needles, haystack): print 'Found' else: 'No luck' would be more inline with what the OP's original javascript.
AB matches? Currently it also matches if AB is somewhere in another word
find_result = re.findall(r'\s+(AB|AG|AS|Ltd|KB|University)\s+', s). This assumes that there are spaces around a world. Obviously for periods, comas, and all other possible ways a word can appear in a sentence, something more complicated is needed.
University|A[BGS]|Ltd|KBorLtd|University|[AK]B|A[GS]... But when you need to change it, that's a hell to maintain! :)