How to filter a connection in python?

Question

I wrote a code to open a socket and then accept the socket and connect it. What is the problem? I want to filter the incoming connection ip. So I wrote a "if" statement for the connecting ip but it wont work. Looking forward for your help!

#!/usr/bin/python           

import socket               

s = socket.socket()         # Create a socket 
host = socket.gethostname() 
port = 12345                # opening a port
s.bind((host, port))        # Bind to the port

s.listen(5)                # Now wait for client connection.
c, addr = s.accept()       # accept the client
c.send('waiting for connection...')  
if '192' in addr:  #---->This is what does not work. 
   print 'Got connection from', addr
   c.send('Thank you for connecting')
   print 'accepted'
else:
   c.close() 
   print 'blocked.'
   print '{0} tried to connect'.format(addr)
print 'a connection was request from', addr
raw_input("Press enter to continue: ")

Are you sure addr is a string containing the IP? maybe it is a tuple that contains the couple (address,port) — Antonio Ragagnin
– Antonio Ragagnin, Commented Jun 16, 2014 at 8:44

Community · Accepted Answer · 2017-05-23 12:05:32Z

1

As we can see here, addr that you get from s.accept() is a tuple containing the ip adress and the port. To check the ip adress use addr[0]

>>> ip='192.168.1.1'
>>> '192' in ip
True
>>> addr=(ip, 2424)
>>> '192' in addr
False
>>> '192' in addr[0]
True

edited May 23, 2017 at 12:05

CommunityBot

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answered Jun 16, 2014 at 8:44

fhdrsdg

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Comments

Simon Fraser · Accepted Answer · 2014-06-16 08:44:10Z

0

'addr' in the above code is a tuple containing the IP address and port number of the far end, it will look something like this:

('127.0.0.1', 48223)

For the above:

>>> '127' in addr
False
>>> '127' in addr[0]
True

Hopefully this gives you enough to modify the code.

answered Jun 16, 2014 at 8:44

Simon Fraser

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