copy a char array to another char array of arrays

Question

what is the best solution to copy a char array -which may contains multiple null characters- to another char arrays of arrays?
for example:

char src[11] = "ab\0cde\0\0fg"
char des[2][6];

at the end

   des[0] should be ---> ab\0cd    +  \0 
   des[1] should be ---> e\0\0fg   +  \0

note: it should be done just in C and not C++

Sergey L. · Accepted Answer · 2014-06-17 10:39:33Z

4

you are looking for memcpy

memcpy(des[0] // target void *
     , src    // source void *
     , 5      // number of bytes to copy
     );
des[0][5] = '\0';

memcpy(des[1]  // target void *
     , src + 5 // source void *
     , 5       // number of bytes to copy
     );
des[1][5] = '\0';

edited Jun 17, 2014 at 10:39

answered Jun 17, 2014 at 10:34

Sergey L.

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5 Comments

osyan Over a year ago

And what about null charechter that should be added at the end of each row of des?

Sergey L. Over a year ago

@osyan edited, didn't quite grasp that you wanted it that way.

user2793162 Over a year ago

@SergeyL.:should not there be &des[0]?

Lundin Over a year ago

Now this is some weird coding style... Keeping the function arguments on multiple lines is good for readability and comments, but usually you put the commas after each argument, on the same row.

Sergey L. Over a year ago

@Lundin everyone in his own style, I do it this way so that I can comment out any line in order to add/remove arguments. Most compilers don't understand an empty argument as the last one, so I always have the comma before.

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