Making an array from a txt list

Question

I want to strip the scores from the file and arrange them in an ordered list where I can print out the 1st, 2nd and 3rd place, here is my code:

scores = []
result_f = open("results.txt")
for line in result_f:
    (name, score) = line.split()
    scores.append = (float(score))
result_f.close()
print("The highest scores were: ")
print(score[0])
print(score[1])
print(score[2])

the console error python gives is:

File "C:\Python34\surfingscores.py", line 5, in scores.append = (float(score)) AttributeError: 'list' object attribute 'append' is read-only

Ashoka Lella · Accepted Answer · 2014-06-22 14:15:57Z

2

scores.append is a function. Instead of using

scores.append = float(score)

try using

scores.append = float(score)

or an alternatively

scores[len(scores):] = float(score)

edited Jun 22, 2014 at 14:15

answered Jun 22, 2014 at 13:42

Ashoka Lella

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adimoh · Accepted Answer · 2014-06-22 13:47:06Z

1

scores.append is a function/method of scores.

You need to make a function call.

scores.append(float(score))

answered Jun 22, 2014 at 13:47

adimoh

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Comments

timgeb · Accepted Answer · 2014-06-22 13:51:11Z

1

You need

scores.append(float(score))

Currently you are trying to assign a float value to the attribute append of the scores list, which is not what you want. The error is thrown because the append attribute of your scores list (which is the function for appending to that list) is read-only and thus explicitly protected from what your current code is doing.

>>> scores = []
>>> scores.append
<built-in method append of list object at 0x7f08964f9638>

edited Jun 22, 2014 at 13:51

answered Jun 22, 2014 at 13:42

timgeb

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