Split one XML file to multiple XML File with XSLT

Question

I have this XML in one file below

<?xml version="1.0" encoding="utf-8"?>
<document>
  <file> <!--File1.xml-->
    <content>content file 1</content>
  </file>
  <file> <!--File2.xml-->
    <content>content file 2</content>
  </file>
  <file> <!--File3.xml-->
    <content>content file 3</content>
  </file>
</document>

How do I write an XSLT to break it to multiple files like below

File1.xml
<?xml version="1.0" encoding="utf-8"?>
<document>
  <file>
    <content>content file 1</content>
  </file>
</document>

File2.xml
<?xml version="1.0" encoding="utf-8"?>
<document>
  <file> 
    <content>content file 2</content>
  </file>
</document>

etc..

Thank you for help.

Are you able to use XSLT 2.0? If so, you should be able to use "result-document". See saxonica.com/documentation/xsl-elements/result-document.html — Tim C
– Tim C, Commented Jun 24, 2014 at 8:32
Do you actually have to use XSLT at all here? If you are using using .Net for the transformation, just load the XML into an XDocument, select all the file elements, iterate over them and output a file for each one. — Tim C
– Tim C, Commented Jun 25, 2014 at 7:22
Yes can do that also but it is the requirement for me to use XSLT because a file can contain more or less data depending on their requirement — zyberjock
– zyberjock, Commented Jun 25, 2014 at 7:27

dogbane · Accepted Answer · 2014-06-24 08:36:01Z

2

With XSL 2.0:

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" indent="yes"/>
    <xsl:template match="/">
        <xsl:for-each select="document/file">
            <xsl:result-document href="file{position()}.xml">
                <document>
                    <xsl:copy-of select="current()"/>
                </document>
            </xsl:result-document>
        </xsl:for-each>
    </xsl:template>
</xsl:stylesheet>

I tested this using Saxon, which supports XSLT 2.0, using the command below:

java -jar saxon9.jar -xsl:transform.xsl -s:input.xml

This command generates three files: file1.xml, file2.xml and file3.xml.

$ cat file1.xml
<?xml version="1.0" encoding="UTF-8"?>
<document>
   <file> <!--File1.xml-->
    <content>content file 1</content>
  </file>
</document>

answered Jun 24, 2014 at 8:36

dogbane

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3 Comments

zyberjock Over a year ago

How about in XSL 1.0, is it doable?

zyberjock Over a year ago

Because as much as possible we want to avoid using third party components. We are using .Net for the transformation. Thanks

dogbane Over a year ago

Not in XSL 1.0. The other alternative is to use xml parsing in .Net. For example, use an xpath (/document/file) to get all the file elements and then iterate over them, writing each one out.

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