Simple regex pattern in C#

Question

I've been trying to do this for some time now, but my Regex skills are pretty bad. I have this text

<td class="red">
    One
</td>
<td>
    Two
</td>

And I want to get the value of "Two". I've tried multiple things like

<td>\n(.*)\n</td>
<td class=\"red\">\nOne\n</td>\n<td>\n(.*)\n</td>

And this is my C# source

foreach (Match m in Regex.Matches(src, pattern, RegexOptions.IgnorePatternWhitespace))
{
    MessageBox.Show(m.Groups[1].Value);
}

I tried changing the RegexOptions with no luck. If anyone could help me it'd be greatly appreciated. Thank you

use HTML agility pack it would be much simpler rather then now — Just code
– Just code, Commented Jun 25, 2014 at 13:24
XElement.Parse("<Your xml fragment">).Elements("td").Last().Value — CodeWeed
– CodeWeed, Commented Jun 25, 2014 at 13:26

krimog · Accepted Answer · 2014-06-25 13:25:43Z

1

Why not simply :

string expression = @"\<td\>[\s]*[A-Za-z]*[\s]*\</td\>";

And if you want to name your group

string expression = @"\<td\>[\s]*(?<groupName>([A-Za-z]*))[\s]*\</td\>";

answered Jun 25, 2014 at 13:25

krimog

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Comments

hwnd · Accepted Answer · 2014-06-25 13:27:01Z

0

Use the s (DotAll) modifier forcing the dot . to match newline sequences as well.

foreach (Match m in Regex.Matches(src, @"(?s)<td>\s*(.*?)\s*</td>"))
         MessageBox.Show(m.Groups[1].Value);

Note: Follow .* with ? for a non-greedy match here.

answered Jun 25, 2014 at 13:27

hwnd

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Avinash Raj · Accepted Answer · 2014-06-25 13:57:55Z

0

Enable dotall(s) modifier to make . to match a newline character.

(?<=<td>)\s*(\w*)\s*(?=<\/td>)

And your code would be,

Regex rgx = new Regex(@"(?s)(?<=<td>)\s*(\w*)\s*(?=<\/td>)");
foreach (Match m in rgx.Matches(input))
Console.WriteLine(m.Groups[1].Value);

answered Jun 25, 2014 at 13:28

Avinash Raj

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