CoffeeScript - How do I retrieve a static array property in class

Question

I just started learning CoffeeScript and I'd like to know what the best practice is for retrieving a static property in a class from a child instance.

class Mutant
    MutantArray: []

    constructor: (@name, @strength = 1, @agility = 1) ->
        @MutantArray.push(@name)

    attack: (opponent) ->
        if opponent in @MutantArray then console.log @name + " is attacking " + opponent else console.log "No Mutant by the name of '" + opponent + "' found."


    @getMutants: () ->
        # IS THIS RIGHT?
        console.log @.prototype.MutantArray

Wolverine = new Mutant("Wolverine", 1, 2)
Rogue = new Mutant("Rogue", 5, 6)

Rogue.attack("Wolverine")

Mutant.getMutants()

I would like my getMutants() method to be static (no instantiation needed) and return a list of Mutant names that have been instantiated. @.prototype.MutantArray seems to work fine, but is there a better way to do this? I tried @MutantArray but that doesn't work.

Thanks!

mkrakhin · Accepted Answer · 2014-06-27 16:46:45Z

1

I think you should define your MutantArray as static field. Then, from non-static methods you should reference it via class and from static methods you access it via @. Like this:

class Mutant
    @MutantArray: []

    constructor: (@name, @strength = 1, @agility = 1) ->
         Mutant.MutantArray.push(@name)

    attack: (opponent) ->
        if opponent in Mutant.MutantArray then console.log @name + " is attacking " + opponent else console.log "No Mutant by the name of '" + opponent + "' found."


    @getMutants: () ->
        # IS THIS RIGHT?
        console.log @MutantArray

edited Jun 27, 2014 at 16:46

answered Jun 27, 2014 at 7:52

mkrakhin

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Comments

Rubén Guerrero · Accepted Answer · 2014-06-27 07:47:23Z

0

I think it is so:

class Mutant
    MutantArray: []

    constructor: (@name, @strength = 1, @agility = 1) ->
        @MutantArray.push(@name)

    attack: (opponent) ->
        if opponent in @MutantArray then console.log @name + " is attacking " + opponent else console.log "No Mutant by the name of '" + opponent + "' found."


    getMutants: () ->
        # IS THIS RIGHT?
        console.log @.MutantArray

Wolverine = new Mutant("Wolverine", 1, 2)
Rogue = new Mutant("Rogue", 5, 6)

Rogue.attack("Wolverine")

Mutant.getMutants()

getMutants must to be a prototype method, and you retrieve the array value with @.getMutants

answered Jun 27, 2014 at 7:47

Rubén Guerrero

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