Reading multiple json values with php

Question

I am trying to read certain values from a json string in php, I am able to do a simple json string with only one value such as

$json = '{"value":"somevalue"}';

Using this:

<?php 
      $json = '{"value":"somevalue"}';
      $obj = json_decode(json_encode($json));
      print $obj->{'value'};
?>

But when i try an get a value from the following json string it throws an error...

$json = '{"field": "title","rule": {"required": "true","minlength": "4","maxlength": "150" }}';

I validated the json on JSONlint but not sure how to access the values within this with php.

Thanks

What error does it throw, and what's the code that throws it? — deceze
– deceze ♦, Commented Mar 15, 2010 at 9:16
Trying to get property of non-object in C:\wamp\www\l\public\grr.php on line 21 — jason
– jason, Commented Mar 15, 2010 at 9:39
you are trying to access an array like an object. use $obj['value'] — knittl
– knittl, Commented Mar 15, 2010 at 9:51

Young · Accepted Answer · 2010-03-15 09:51:25Z

3

You can try this:

$json = '{"field": "title","rule": {"required": "true","minlength": "4","maxlength": "150" }}'; 
//since $json is a  valid json format you needn't encode and decode it again
$obj = json_decode($json);
print_r($obj->filed);
print_r($obj->rule);

answered Mar 15, 2010 at 9:51

Young

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1 Comment

Young Over a year ago

@jason,please don't always leave your questions an unanswered state,and that would be some kinda of negative record.

jackbot · Accepted Answer · 2010-03-15 09:15:06Z

0

You can pass true as a second parameter to json_decode() to get the results as an array

$my_arr = json_decode($json, true);
var_dump($my_arr);

Should help you. You can then step through the array as you would normally.

answered Mar 15, 2010 at 9:15

jackbot

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Comments

knittl · Accepted Answer · 2010-03-15 09:15:41Z

0

use var_dump to print out the object with all it's members and hierarchy. you should then be able to find the value you are looking for

answered Mar 15, 2010 at 9:15

knittl

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3 Comments

jason Over a year ago

thats not my problem, I can print out all the values but i am unable to access one of the values: <pre> $json = '{"field": "title","rule": {"required": "true","minlength": "4","maxlength": "150" }}'; $json = json_encode($json); $obj = json_decode($json,true); print $obj -> {'field'}; </pre> ** Trying to get property of non-object in C:\wamp\www\l\public\grr.php on line 21 **

jackbot Over a year ago

If you pass true to json_decode(), it'll give you back an array, not an object. You need to access elements in the way you normally would for an array.

deceze Over a year ago

@jason First, please do not post code in comment fields, it's messy. :) Second, when using json_decode(..., true), the result is indeed not an object, but an array. Yet you're trying to access it like an object. The error message is quite correct.

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