Shell Script - Unix

Question

grep "<ValidateXYZResponse" filename.log* | grep -v "<ResponseCode>000<ResponseCode>"

Above command works fine in UNIX where grep -v excludes the records having response code "000"

However, along with "000", I need to exclude the following response codes too: "404", "410", "403", "406"

I am new to unix shell script.

If anyone knows how to do it, please help. Appreciate your help. Thanks.

Read some basic documentation on regex. There is something called alternation. — devnull
– devnull, Commented Jul 1, 2014 at 9:57
This question appears to be off-topic because it is about unwillingness to RTFM. — devnull
– devnull, Commented Jul 1, 2014 at 9:58
@devnull - I sure will learn the basics. Asked question here because I have to send some reports quickly and this is the first time I am using unix shell script. — Akshaya
– Akshaya, Commented Jul 1, 2014 at 10:06
It would have taken you much less than the time in which you received the first answer only if you were willing to RTFM. Good luck! — devnull
– devnull, Commented Jul 1, 2014 at 10:08

Kent · Accepted Answer · 2014-07-01 09:59:11Z

3

you can do (foo|bar|blah) to implement OR in regex. Like:

grep ...|grep -v '<...>\(000\|40[346]\|410\)<...>'

or

grep ...|grep -vE '<...>(000|40[346]|410)<...>'

detailed explanation about regex-alternation:

answered Jul 1, 2014 at 9:59

Kent

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Comments

zx81 · Accepted Answer · 2014-07-01 09:57:13Z

1

grep "<ValidateXYZResponse" filename.log* | grep -Pv "<ResponseCode>(?:000|40[346]|410)<ResponseCode>"

The (?:000|40[346]|410) non-capturing group in the middle gives a list of codes to exclude
| is the alternation (OR) operator
[346] means one character that is either 3, 4 or 6

answered Jul 1, 2014 at 9:57

zx81

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grep -P (for perl regexen?) is a GNUism unsupported by many grep implementations. grep -E is more portable.