passing variables in form_open() in codeigniter

Question

Good day all. I'm new to codeigniter and I'm trying to pass a variable from one view page to another. But I get error and after a lot of tries still couldn't figure it out.

This is the Model code:

function get_post($postID){
    $this->db->select()->from('khanposts')->where(array('post_id'=>$postID))->order_by('fullname', 'desc');
    $query=$this->db->get();
    return $query->result_array();
}

function update_post($postID, $data)
{
    $this->where('post_id', $postID);
    $this->db->update('khanposts', $data);
}

This is the Controller code:

function editpost($postID)
{
    $data['success']=0;
    if($_POST){
        $data_post=array(
            'fullname'=>$_POST['fullname'],
            'dob'=>$_POST['dob'],
            'blood'=>$_POST['blood'],
            'village'=>$_POST['village'],
            'occupation'=>$_POST['occupation'],
            'company'=>$_POST['company'],
            'email'=>$_POST['email'],
            'contact'=>$_POST['contact'],
            'password'=>$_POST['pass'],
            'marry'=>$_POST['marry']);
        $this->khanpost->update_post($postID, $data);
        $data['success']=1;
    }
    $data['post']=$this->khanpost->get_post($postID);
    $this->load->view('edit_post', $data);
}

This is the code of View page which passes the value to edit_post view page:

foreach ($posts as $row){
<tr><td><a href="' .base_url(). 'khanposts/editpost/' .$row['post_id']. '" target="_blank"><i>Edit</i></a></td></tr>';
}

This is code of edit_post view page where it must get the value of $row['post_id']:

echo form_open(base_url().'khanposts/editpost/'.$row['post_id']);
echo '<b>Full Name: </b>';
$data_form=array('name'=>'fullname', 'size'=>30, 'id'=>'fullname', 'class'=>'inputstyle', 'value'=>$row['fullname'] );
echo form_input($data_form);

How do I assign the passsed variable($row['post_id']) in form_open()? Any solution will be really helpful. Tnx.

you can use form_open(base_url().'khanposts/editpost/?id='.$row['post_id']) and in controller check for $this->input->get('id') — Karan Thakkar
– Karan Thakkar, Commented Jul 4, 2014 at 8:01

Bora · Accepted Answer · 2014-07-04 08:47:03Z

3

As far as I understand the problem;

Pass PostID to view in editpost function:

function editpost($postID)
{
   ...
   $data['postID'] = $postID;
}

Get it in view page like:

echo form_open(base_url('khanposts/editpost/'.$postID));

You should load form helper:

$this->load->helper('form');

And your data_form input:

$data_form = array('name'=>'fullname', 'size'=>30, 'id'=>'fullname', 'class'=>'inputstyle', 'value' => $post['fullname']);

You should use row_array instead of result_array, because of you get single post.

function get_post($postID)
{
    $this->db->select()->from('khanposts')->where(array('post_id'=>$postID))->order_by('fullname', 'desc');
    $query=$this->db->get();
    return $query->row_array();
}

edited Jul 4, 2014 at 8:47

answered Jul 4, 2014 at 7:32

Bora

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12 Comments

Bora Over a year ago

You write $data['postID'] = $postID; before the `$this->load->view``line, right?

Bora Over a year ago

Did you look form action url, is it empty? And try this variable in view page echo form_open(base_url('khanposts/editpost/'.$post['post_id']));

Bora Over a year ago

@SinOscuras And you should load form helper. Updated answer

Bora Over a year ago

@SinOscuras Hmm.. Could you dump it in view page? var_dump($post); you will see..

Bora Over a year ago

@SinOscuras Answer is updated. You should use row_array instead of result_array, because of you get single post.

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