i want to check 2 patterns using regex.
can i check those both patterns in the same time (like if(condition1 | condition2) condition).
any idea?
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2 Answers
You can do it exactly the way you did, with pipe separating the two+ expressions
For instance: The regular expresion (abc)|(def) would match abc OR def
answered Mar 16, 2010 at 18:52
Daniel Silveira
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1 Comment
Cascabel
That is the syntax. The regular expression
pattern1|pattern2 means "match pattern1 or pattern2".It really depends - namely, you can design your regex with "or" modifiers like this "(match this)|(or this)". If you use carefully designed regex, you only need to do this:
Pattern p1 = Pattern.compile(regex)
Matcher m = p1.matcher(searchstring)
Once. This is probably the most efficient way to go about things. The other option is to run two matcher/pattern object pairs, run find operations until find returns false than count the number of outputs. If they're both > 0 you're in business. The other option is if you only need one or more matches, to do:
if ( matcher1.find() & matcher2.find() )
{
...
}