Move or shift array element to last postion by condition + ruby array

Question

I need to shift an element to last position by condition. For ex. [1,2,3] and to put 1 in last in array, without executing unnecessary loops.

o/p [2,3,1] for the above condition array will be dynamic and put particular element on last by condition.

I tried like this:

sd = [1,2,3]
sd.map{|d| sd.last(d) if d ==1 }

but the output is [[3], nil, nil]

Arup Rakshit · Accepted Answer · 2014-07-05 10:49:38Z

3

We have Array#rotate method :-

[3] pry(main)> a = [1,2,3]
=> [1, 2, 3]
[4] pry(main)> a.rotate(1)
=> [2, 3, 1]
[5] pry(main)> a.rotate(2)
=> [3, 1, 2]

In your case, you should pass 1 as argument to the method #rotate. But 1 is default argument to the #rotate method, so you can omit it too. bang version of #rotate also exist.

edited Jul 5, 2014 at 10:49

answered Jul 5, 2014 at 10:01

Arup Rakshit

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