python slicing substrings or strings

Question

If I have a string 'banana peel' and I want to break it down to a width of 3 characters as in:

'ban'
'ana'
'pee'
'l'

How would I go about that? How would I remove the space/whitespace between 'banana' and 'peel' that is in the middle of the string and create the results above?

Only things that come to mind are things like list() and strip()

Removing the spaces is simple enough with s = s.replace(" ", ""). As for the second question, does this address your issue? — David Robinson
– David Robinson, Commented Jul 7, 2014 at 3:45

Will Richardson · Accepted Answer · 2014-07-07 03:49:10Z

1

Just like this:

string = "banana peel"
string = string.replace(" ", "")
results = []
for i in range(0, len(string), 3):
    results.append(string[i:i + 3])
print(results)

replace(" ", "") replaces all the spaces with nothing, giving bananapeel. range(0, len(string), 3) will give a list of numbers from 0 to the length of the string with an interval of 3. Each set gets added to the array for you to print in the end.

answered Jul 7, 2014 at 3:49

Will Richardson

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6 Comments

Robert Over a year ago

all righty then. the results.append(string[i:i + 3]) is basically the same as: results.append(string[0:0 + 3]) in the first run? I am fairly new to slicing.

Will Richardson Over a year ago

Yes, it'll give you all the items from 0 inclusive to 3 exclusive, ie the 0th 1st and 2nd items.

Robert Over a year ago

oooh thanks man. Yes I remember in slicing the last number basically means," up to but not including"

Peter Gibson Over a year ago

You could also use a list comprehension instead of the for loop+append: [string[i:i+3] for i in range(0, len(string), 3)]

Robert Over a year ago

true but that is a little too advanced for me at the momment

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