php - issue with date-format

Question

I am struggeling with some basic date-formatting and echo the right number for "Days Left". This is the code:

date_default_timezone_set('Europe/Oslo');
$dateNow = date('d/m/Y', time());
$dateStart = date('d/m/Y', strtotime('01/08/2014'));
$dateFinished = date('d-m-Y', $dateStart + strtotime("+62 days"));
$daysLeft = intval($dateFinished-$dateNow);

echo($dateNow. "<br>");
echo($dateStart. "<br>");
echo($daysLeft. "<br>");

This is the echo: 07/07/2014 01/08/2014 -6

It seems like dateStart is interped as a wrong format. I have tried with both - and /, but nothing better.

What have i done wrong? Just the math or is it the logic?

var_dump($dateStart + strtotime("+62 days")); --- never assume, always check. — zerkms
– zerkms, Commented Jul 7, 2014 at 11:44

Yannici · Accepted Answer · 2014-07-07 12:37:17Z

2

I recommend to use OOP (Object-oriented) in this case. It is easier to write and easier to understand.

Just made a simple and short script:

<?php
date_default_timezone_set('Europe/Oslo');
$dateNow = new DateTime('now');
$dateStart = new DateTime('2014-08-01');
$dateFinished = new DateTime($dateStart->format('Y-m-d'));
$dateFinished->add(new DateInterval('P62D'));
$daysLeft = $dateFinished->diff($dateNow);

echo($dateNow->format('d/m/Y'). "<br>");
echo($dateStart->format('d/m/Y'). "<br>");
echo($daysLeft->format('%d'). "<br>");
?>

edited Jul 7, 2014 at 12:37

answered Jul 7, 2014 at 11:56

Yannici

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2 Comments

simonkaspers1 Over a year ago

Doesn't this modify datestart to? $dateStart->add(new DateInterval('P62D') @Yannici

Yannici Over a year ago

Of course. Thank you for the hint :P I just edited my answer.

colburton · Accepted Answer · 2014-07-07 11:44:56Z

2

$dateStart is a string. You need to do:

$dateStart = date('d/m/Y', strtotime('01/08/2014'));
$dateFinished = date('d-m-Y', strtotime("+62 days", strtotime('01/08/2014')));

For more sophisticated date calculations consider DateTime().

answered Jul 7, 2014 at 11:44

colburton

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Comments

Justinas · Accepted Answer · 2014-07-07 11:46:09Z

1

If your PHP is 5.3+, than you can use DateTime class and calculate difference between dates:

$date1 = new DateTime("2007-03-24");
$date2 = new DateTime("2009-06-26");
$interval = $date1->diff($date2);

echo "difference " . $interval->y . " years, " . $interval->m." months, ".$interval->d." days ";

OR

echo "difference " . $interval->days . " days ";

answered Jul 7, 2014 at 11:46

Justinas

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