Drop Down for Selenium and Python

Question

I have the drop-down menu for which the source is as below:

<select name="issuer">
<option selected="selected" value="15">MBBTampereRootCA
</option><option value="66222">OMS_CA1
</option><option value="66225">OMS_CA2
</option><option value="71463">stefanSpiel
</option></select>

and I need to select "stefanSpiel" please tell me how can i do that ??

I tried with Multiple possible options, but not successful.

I have tried these options:

browser = webdriver.Firefox()
browser.find_element_by_css_selector("option.stefanSpiel")
browser.find_element_by_link_text('option.stefanSpiel');

and also these:

'element = browser.find_element_by_name("issuer")'
'target = select (option, stefanSpiel)'
'action_chains = ActionChains(browser)'
'action_chains.drag_and_drop(element, target)'

'ActionChains(browser).move_to_element(element).click(target).perform()'

But all i got is : 'selenium.common.exceptions.NoSuchElementException:'

Thanks,

I don't know about python but I have done that in Java, could it help you if I paste it here if you know how to adapt it to python ? — singe3
– singe3, Commented Jul 7, 2014 at 14:20
With a bit more html it might be easier to help you. The containing select element may have an id that could make it quite simple to get it via selenium. — Sebastian
– Sebastian, Commented Jul 7, 2014 at 20:32
I have tried these options: browser = webdriver.Firefox() browser.find_element_by_css_selector("option.stefanSpiel") browser.find_element_by_link_text('option.stefanSpiel'); and also these: 'element = browser.find_element_by_name("issuer")' 'target = select (option, stefanSpiel)' 'action_chains = ActionChains(browser)' 'action_chains.drag_and_drop(element, target)' 'ActionChains(browser).move_to_element(element).click(target).perform()' But all i got is : 'selenium.common.exceptions.NoSuchElementException:' Thanks, — Jay
– Jay, Commented Jul 8, 2014 at 6:16

ro.e · Accepted Answer · 2014-07-07 20:25:15Z

1

One way to do it is by clicking the 'select' element. This will 'open' the drop-down and make all the drop-down options visible to our driver. Now we will need to click the desired element.

For example, lets take a look at the following html (it's very similar to the html you provided) I took it from http://www.tizag.com/htmlT/htmlselect.php:

<select name="selectionField"> 
  <option value="CA">California -- CA </option>
  <option value="CO">Colorado -- CO</option>
  <option value="CN">Connecticut -- CN</option>
</select>

For this example I will use xpaths. Lets say I have the xpath of the 'select' element:

xpath = '/html/body/table[3]/tbody/tr[1]/td[2]/table/tbody/tr/td/div[4]/select'

I would like to select the option "Connecticut -- CN"

One way to do it is this:

from selenium import webdriver

driver  = webdriver.Firefox()

# navigate to the page that contains the html I provided  
driver.get('http://www.tizag.com/htmlT/htmlselect.php')

# the xpath of the <select> elemnt
xpath = '/html/body/table[3]/tbody/tr[1]/td[2]/table/tbody/tr/td/div[4]/select'

# click on the <select> element to open the dropdown
driver.find_element_by_xpath(xpath).click()

# select the desired option
driver.find_element_by_xpath(xpath+'/*[contains(text(), "Connecticut -- CN")]').click()

answered Jul 7, 2014 at 20:25

ro.e

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1 Comment

sparkyShorts Over a year ago

XPaths are brittle if you are working with multiple browsers since the XPaths would be different. I've had more success with driver.find_element_by_link_text("YourSelectionHere") when working with options in a select element.

Mark Rowlands · Accepted Answer · 2014-07-08 07:59:43Z

0

I would suggest you use the Select() class as it exists to handle select elements.

from selenium.webdriver.support.select import Select

select_element = Select(driver.find_element_by_name("issuer"))
select_element.select_by_visible_text("stefanSpiel")

answered Jul 8, 2014 at 7:59

Mark Rowlands

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Comments

Jay · Accepted Answer · 2014-07-08 09:10:43Z

0

Thanks all... Tried as below and it works... not sure to what extent it is good:

element = browser.find_element_by_name("issuer")
element.send_keys('stefanSpiel' + Keys.RETURN)

Thanks again :)

answered Jul 8, 2014 at 9:10

Jay

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