unix shell sub string?

Question

I want to extract substring till the point the last numeric ends.

for example:

In the string "abcd123z" , I want the output to be "abcd123"

In the string "abcdef123gh01yz" , I want the output to be "abcdef123gh01"

In the string "abcd123" , I want the output to be "abcd123"

How to do this in the unix shell?

Avinash Raj · Accepted Answer · 2014-07-10 11:54:43Z

2

Try this sed command,

sed 's/^\(.*[0-9]\).*$/\1/g' file

Example:

$ echo 'abcdef123gh01yz' | sed 's/^\(.*[0-9]\).*$/\1/g'
abcdef123gh01

answered Jul 10, 2014 at 11:54

Avinash Raj

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Comments

anubhava · Accepted Answer · 2014-07-10 11:54:57Z

1

You can do this in BASH regex:

str='abcdef123gh01yz'
[[ "$str" =~ ^(.*[[:digit:]]) ]] && echo "${BASH_REMATCH[1]}"
abcdef123gh01

answered Jul 10, 2014 at 11:54

anubhava

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Yes I clearly mentioned BASH because of that since OP tagged the question with BASH

He tagged bash and ksh

Deleted User · Accepted Answer · 2014-07-10 11:59:48Z

1

tmp="${str##*[0-9]}"     # cut off all up to last digit, keep intermediate
echo "${str%$tmp}"        #  remove intermediate from end of string

answered Jul 10, 2014 at 11:59

Deleted User

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