Using for loop to get for specific iteration result in javascript

Question

I need help in somewhere in javascript

var obj = jQuery.parseJSON(data.d);

This ajax call result returns some data (around 31).

Here is an example:

obj[0] = 10, obj[1]=20 ,obj[2]=30 , obj[4]=21,obj[5]=16,obj[6]=54 here I want to get value of

obj[0] and ob[4] using for loop . And I also need to do this for obj[10] and obj[14] the difference will be 5 between the i values .

Any idea or help?

Why would you use a for loop if you know you want 0 and 4? just get 0 and 4. (or 8 according to your title....) — user400654
– user400654, Commented Jul 10, 2014 at 19:29
Ah, so you want every 5th. that makes a lot more sense. Though i still dont know where 8 in your title comes in. — user400654
– user400654, Commented Jul 10, 2014 at 19:31
I want to use same process for others . you know , the Difference will be 5 between I values — one1day
– one1day, Commented Jul 10, 2014 at 19:32
You want obj[0] and then obj[4] .. then the difference is 4 and not 5. right? — Rahul
– Rahul, Commented Jul 10, 2014 at 19:38

Rahul · Accepted Answer · 2014-07-10 19:35:25Z

1

You can do something like this (a pseudo code)

int i = 0;

while(i < 31)
{
 print(i);
 i = i + 4; 
}

answered Jul 10, 2014 at 19:35

Rahul

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3 Comments

user400654 Over a year ago

definitely should be +5, since he always wants 0 and 4. 0,4,10,14,20,24,30

Rahul Over a year ago

@KevinB, home come? to me it looks like a skip of 4 index and not 5.

Rahul Over a year ago

@KevinB, accepted. Unless OP clarifies it, it's indeed strange.

lante · Accepted Answer · 2014-07-10 19:35:57Z

1

If i understood, you want to skip 5 on each step:

var array = 'abcdefghijklmnopqrstuvwxyz'.split(''); // something that generates an array just to show an example

var i = 0;

for (; i < array.length;) {
    console.log(i, array[i]);
    i += 5;
}

see fiddle

answered Jul 10, 2014 at 19:35

lante

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Comments

ltalhouarne · Accepted Answer · 2014-07-10 19:36:39Z

1

var iterator=0;
for (i = 0; i < obj.length; i++) { 
    if(i == iterator){
       alert(obj[iterator]);
       iterator= iterator + 4;
    }
}

edited Jul 10, 2014 at 19:36

answered Jul 10, 2014 at 19:31

ltalhouarne

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1 Comment

one1day Over a year ago

There is actulally small issue I am having. since I want to get obj0 and obj4 also obj5 and obj9 , it makes problem when I try to get obj5 because its adding +4 each time

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