Bash Loop 2 Arrays

Question

I'm trying to create a loop for a couple of arrays but I get this error:

./bash.sh: 3: ./bash.sh: source[0]=/media/jon/my\ directory/: not found

This is what my code looks like:

sourceFiles[1]=/media/jon/ACER/Documents\ and\ Settings/Laura/Documents/Shared
destinationFiles[1]=/media/jon/My\ Book/Shared

for index in ${!sourceFiles[@]}
do
  sudo rsync -a --delete ${sourceFiles[$index]} ${destinationFiles[$index]}
done

I'm some what green to bash files and this is terribly frustrating that doing a simple loop is so difficult.

Update

I needed a #!/bin/bash at the top per the correct answer.

Run your script through SpellCheck. And personally, I think this syntax would be simpler if you want to use indexes. — Reinstate Monica Please
– Reinstate Monica Please, Commented Jul 14, 2014 at 0:36
@BroSlow Thanks, I'll change it over, it would even be nicer if I could just use a map2 syntax! Or even just range(0..4).map. — Jon49
– Jon49, Commented Jul 14, 2014 at 2:02

pdw · Accepted Answer · 2014-07-14 00:40:04Z

2

Your code looks ok. I think you're not using bash though ("not found" is not a bash error message). Are you perhaps using /bin/sh? On many systems that's a minimal POSIX shell, not bash.

A POSIX shell would not recognize sourceFiles[1]=... as an assignment and would consequently run it as a command. Hence the "not found" error.

answered Jul 14, 2014 at 0:40

pdw

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Comments

morgano · Accepted Answer · 2014-07-14 00:43:27Z

2

Try enclosing in double quote your variables in your sudo line:

sudo rsync -a --delete "${sourceFiles[$index]}" "${destinationFiles[$index]}"

answered Jul 14, 2014 at 0:43

morgano

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1 Comment

Jon49 Over a year ago

You were both right, but I had tried what you suggested before, but the underlying problem was pdw's answer. Thanks for your help.

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