PHP use variable to populate associative array

Question

I am currently populating an associative array like this:

$plates_data['data'][] = array("drilldown"=>$sImageUrl, "type"=>$Type, "job_no"=>$Job_No, "customer"=>$Customer);

I'd like to be able to do something like this:

$myvar = '"drilldown"=>$sImageUrl, "type"=>$Type, "job_no"=>$Job_No, "customer"=>$Customer';

 $plates_data['data'][] = array($myvar);

This doesn't work, can someone tell me what i'm doing wrong?

What are you trying to accomplish? In the scenario provided your second option is just extra lines and wouldn't result in shorter code — sharf
– sharf, Commented Jul 15, 2014 at 0:49
you are adding an array that contains a single entry which is a string to the next element in the data element of the $plates_data array. — doublesharp
– doublesharp, Commented Jul 15, 2014 at 0:49
variables inside single quotes will not be expanded. also not sure what you are trying to accomplish. — doublesharp
– doublesharp, Commented Jul 15, 2014 at 0:49

Mijoe · Accepted Answer · 2014-07-15 00:50:00Z

2

You can use it like this

$array_holder = array("drilldown"=>$sImageUrl, "type"=>$Type, "job_no"=>$Job_No,"customer"=>$Customer);

 $plates_data['data'][] = $array_holder;

answered Jul 15, 2014 at 0:50

Mijoe

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2 Comments

user3101337 Over a year ago

This works, thanks so much!. I have to use the array more than once in a script. If I had to change entries, I had to do it twice, now I can do it once.

Mijoe Over a year ago

You can directly use it like this $plates_data['data'][] = array("drilldown"=>$sImageUrl, "type"=>$Type, "job_no"=>$Job_No,"customer"=>$Customer);

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