I have a bash script wherein I need to check an array based on a condition and if it matches I need to print the lines after that particular match. My code is below:echo ${myArray[(($k+1))]} doesn't work .
i=0;
for j in `cat sdp_aDT_dhk1smc3_Periodic_20140711.log`
do
array[$i]=$j;
i=$(($i+1));
done
k=0;
for k in myArray;
do
if myArray[$k]="MEMORY" ; then
echo ${myArray[(($k+1))]}
fi
done
If you just want to print the lines that match with your particular condition, please try
myArray=`cat sdp_aDT_dhk1smc3_Periodic_20140711.log`
for k in $myArray;
do
if [ "$k" = "MEMORY" ]
then
echo "$k"
fi
done
You can read that file contents into an array plain and simple with:
array=($(cat fileName))
No loop necessary for that.
Now, to your original question: You seem to mix up array and myArray, or are they two different things? Let's assume they are meant to be the same; so then I think you want to output the items directly after the items MEMORY (that's what your code looks like). You can do that like this:
flag=false
for k in "${array[@]}"
do
$flag && echo "$k"
if [ "$k" = "MEMORY" ]
then
flag=true
else
flag=false
fi
done
Simply:
#!/bin/bash
readarray -t myArray < sdp_aDT_dhk1smc3_Periodic_20140711.log
for i in "${!myArray[@]}"; do
if [[ ${myArray[i]} == 'MEMORY' ]]; then
printf '%s\n' "${myArray[@]:i + 1}"
break
fi
done
readarray converts lines from input to array${!myArray[@]} populates the indices, not the elements themselvesprintf '%s\n' prints every argument as a single line (creates multiple lines)."${myArray[@]:i + 1}" represents all elements after the matched element and expands to multiple arguments.Refer to the Bash Reference Manual for everything.
$before(($k+1)).