a = [1, 2, 3..9, 10, 15, 20..43]
print a.include?(5) # Returns false
I was expecting it to return true, but 3..9 is not translated to [3,4,5,6,7,8,9].
I am missing something silly but I can't figure it out. Basically I want to initialize it with both regular fixnums and ranges.
You have to splat it
a = [1, 2, *3..9, 10, 15, 20..43]
a.include?(5) # => true
*1..1_000_000_000_000. The range is a very efficient way of expressing a big sequence, so if you're working with large ranges it'd be better to implement a smarter conditional test that knows how to compare against individual values, and for inclusion within ranges.
If you would like a "lazier" approach that doesn't require you to convert ranges into array elements, try using the === (case equality) operator.
a = [1, 2, 3..9, 10, 15, 20..43]
a.any? { |x| x === 5 }
I recommend using this approach since it's far more efficient than splatting the range into separate elements.
Another solution, without splat.
a = [1, 2, 3..9, 10, 15, 20..43]
a.any? {|i| i.kind_of?(Range) ? i.include?(5) : i == 5 }
# => true
