How should i declare a char array whose size ranges from 1 to 100 and I cannot make an array of size 100 because i have to make many arrays. My input is:
"bjomboleji";
"bnmjsjbfhaihfaihfga";
"zbihgfbjbnsdfbnbfkj";
"bnxbz";
and i have to check the common occurence of characters.
Use ArrayList for dynamic array.
List<Chracter> array = new ArrayList<Chracter>();
Use a StringBuilder. It is a "mutable sequence of characters."
This is a better solution than a List<Character> as it avoids the need to create Character objects from char primitives.
This is a better choice than manipulating a String as String objects are immutable and manipulation results in additional objects being created.
Use a String to assign the value, then use toCharArray to convert to an array (if you really need a character array)
Variable length char is basically interface CharSequence which is implemented by String, StringBuilder, StringBuffer. So you can use any of it for variable char array.
To my understanding you need to count occurrences of a character in a string.If that's the case here is an example. there is no need to convert it to char array
public class Test {
public static void main(String[] args) {
String x="dhakjkfhajfhuagjkadmnfd";
String y="tskashguadmnsdm,as";
String Check_Character="s";
//Availability
System.out.println("X has Check_Character :"+x.contains(Check_Character)); //false
System.out.println("Y has Check_Character :"+y.contains(Check_Character));//true
//Number of occurrences
System.out.println("X has Check_Character :"+((x+" ").split(Check_Character).length-1)+" : times");//0 times
System.out.println("Y has Check_Character :"+((y+" ").split(Check_Character).length-1)+" : times");//4times
}
}
Otherwise you can use a list instead of an array or use this.
String z="dhakjkfhajfhuagjkadmnfd";
char c[]=z.toCharArray();
