PHP: Find last occurrence in string

Question

I am trying to drop the last vowel in a string. For example:

$string = 'This is a string of words.';

$vowels = array('a','e','i','o','u');

if (in_array($string, $vowels)) {

    // $newstring = '' // Drop last vowel.

}

echo $newstring; // Should echo 'This is a string of wrds.';

How can I do this?

Thanks

A generic answer to the question in your title is the use of strrpos — Clément Malet
– Clément Malet, Commented Jul 21, 2014 at 19:48

Daniel Aranda · Accepted Answer · 2014-07-21 20:11:40Z

2

With a regular expression we could do it:

$str = 'This is a string of words.';
echo preg_replace('/([aeiou]{1})([^aeiou]*)$/i', '$2', $str);
//output: This is a string of wrds.

Explaining a bit more the regular expression:

$ <- the end of the phrase
([aeiou]{1}) <- looks for one vowel
([^aeiou]*) looks for any that is not a vowel

edited Jul 21, 2014 at 20:11

answered Jul 21, 2014 at 19:44

Daniel Aranda

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4 Comments

sanath_p Over a year ago

can you explain the regular expression ? .Will be helpful for many .I am the guy who posted 8 line answer to this question . :p

MultiDev Over a year ago

Yes, thank you for your answer, it seems to work, but could you please explain the expression?

Daniel Aranda Over a year ago

Adding explanation in the answer @JohnRobinson

ash108 Over a year ago

you can safely remove (.*) and $1 from regex and replacement string resp.

sanath_p · Accepted Answer · 2014-07-21 20:00:28Z

0

Hope this works

$string = 'This is a string of words.';

$words = explode(" ", $string);

$lastword = array_pop($words);

$vowels = array("a", "e", "i", "o", "u", "A", "E", "I", "O", "U", " ");
$newlastword = str_replace($vowels, "", $lastword);

$newstring='';
foreach ($words as $value) {
    $newstring=$newstring.' '.$value;
}
$newstring=$newstring.' '.$newlastword;
echo $newstring;

edited Jul 21, 2014 at 20:00

answered Jul 21, 2014 at 19:50

sanath_p

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8 Comments

PeeHaa Over a year ago

$string = 'This is a string of words with multiple vowels.';

PeeHaa Over a year ago

+ doesn't do what you think it does

PeeHaa Over a year ago

$newlastword is not used

Clément Malet Over a year ago

It won't work if the last word doesn't contain any wovel btw.

sanath_p Over a year ago

now it works .@malet it works because nothing will be replaced

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