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I want to get style.css from this string using RegEx

http://domain.net/jitwp/wp-content/themes/strappress/style.css?ver=3.1.1

So far, I've tried \/(?:.(?!\/)) but it gets /style.css?ver=3.1.1. I'm not sure how to ignore the query string at the end or skip the forward slash.

2 Answers 2

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You can use the following regex:

[^/]+\.css

Or use \w which matches word characters:

\w+\.css

Live Demo

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2 Comments

@jugg1es it does, see above demo.
Short and sweet, +1 :)
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If I were you I would use the following regex

[\w_\-]+\.css

Because the following inludes whitespace characters

[^/]+\.css

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