I have a string of data like FF0000FF and I want to write that to a file as raw 8-bit bytes 11111111 00000000 00000000 11111111. However, I seem to end up getting way to much data FF turns into FF 00 00 00 when using struct.pack or I get a literal ASCII version of the 0's and 1's.
How can I simply take a string of hex and write that as binary, so when viewed in a hex-editor, you see the same hex string?
You're looking for binascii.
binascii.unhexlify(hexstr)
Return the binary data represented by the hexadecimal string hexstr.
This function is the inverse of b2a_hex(). hexstr must contain
an even number of hexadecimal digits (which can be upper or lower
case), otherwise a TypeError is raised.
import binascii
hexstr = 'FF0000FF'
binstr = binascii.unhexlify(hexstr)
You could use bytes's hex and fromhex like this:
>>> ss = '7e7e303035f8350d013d0a'
>>> bytes.fromhex(ss)
b'~~005\xf85\r\x01=\n'
>>> bb = bytes.fromhex(ss)
>>> bytes.hex(bb)
'7e7e303035f8350d013d0a'
In Python 3.x you can just use the b prefix in front of modified form of the string, and then write it out to a binary file like so:
hex_as_bytes = b"\xFF\x00\x00\xFF"
with open("myFileName", "wb") as f: f.write(hex_as_bytes)
