I practice how to print unicode in python
My question is: how can I edit the code below to translate to unicode to print the result just 2014-07-16 ?
print 'day: %s \n' %(releaseday)
My original output : day: [u'2014-07-16']
The result I want is: day:2014-07-16
I'd try print u'day: %s \n' %(unicode(releaseday)) And It didn't work
Please teach me Thank you
If print gives [] in output then probably you have list in releaseday
You can:
1) get first element from that list
print 'day: %s \n' % releaseday[0]
2) concatenate all elements from list
print 'day: %s \n' % ''.join(releaseday)
3) iterate elements from list and print it separatly
for x in releaseday:
print 'day: %s \n' % x
But this is basic knowledge in "pure" python and have nothing to do with scrapy.
Since this is a Scrapy related question and I assume this is what the extract() returned - set TakeFirst() output processor on that specific field:
Returns the first non-null/non-empty value from the values received, so it’s typically used as an output processor to single-valued fields.
from scrapy.contrib.loader.processor import TakeFirst
class Product(scrapy.Item):
day = scrapy.Field(output_processor=TakeFirst())
Here's what it does on the console:
>>> from scrapy.contrib.loader.processor import TakeFirst
>>> proc = TakeFirst()
>>> proc([u'2014-07-16'])
u'2014-07-16'
TakeFirst()is the recommended way to get a first value from an extracted list. If you are usingextract()to get the list, you can just useextract_first()to get the first item orNonenowadays.