I have an array of user records, and I would like to sort the users based on priority, which is stored in an array of strings and this array is always changing.
so if i have users =
User id: 1, username: "so_admin", priority: "Monday"
User id: 2, username: "so_staff", priority: "Wednesday"
priority = ["Wednesday","Tuesday","Friday"]
How can I sort my users so that users where their priority is "Wednesday" are listed first, etc.
You can do as
users.sort_by { |u| priority.index(u.priority) || priority.size }
The above sorting is done, with the assumption that the below Array will be sorted as per your need, will hold all uniq values. users array then will use the index of the sorted array.
priority = ["Wednesday","Tuesday","Friday"]
Returns the index of the first object in
arysuch that the object is==toobj. Returnsnilif no match is found.
priority array doesn't hold all weekdays, rather 3. I thought, if any users has priority, which is not present in the priority array, let those users be placed in the last array. Suppose, for any user there is a priority, "Sunday", then, that user will be given lowest priority. How ?
Look at the expression priority.index(u.priority) || priority.size, now with above mentioned sample, priority.index("sunday") gives nil, and right hand side expression of the || will be evaluated, i.e. priority.size, which 3. That's how that user will be moved to the tail of the array.
