Scroll down html table using selenium and python

Question

I am trying to scroll down an HTML table until the last row is visible, the table initially loads about 20 rows and then loads more as I scroll down. I am using selenium webdriver and python to automate this process but so far i am stuck as my code below is scrolling down the whole page instead of this particular table which is passed as an argument in the function.

here is my code the web element to be scrolled is passed as an argument as well as the number of times it will be scrolled down

def scroll_down_element(self, element, times):
    try:
        action_chain = ActionChains(self.browser)
        counter = 0
        while(counter < times):
            element.send_keys(Keys.ARROW_DOWN)
            counter += 1
            sleep(0.25)
    except Exception as e:
        print 'error scrolling down web element', e

All suggestions are welcome

Bob Ezuba · Accepted Answer · 2014-08-05 21:24:55Z

4

This is the code that I resorted to after trying a few different combinations of javascript and other selenium methods. Space scrolls down deeper than ARROW_DOWN or the DOWN Key.

def scroll_down_element(self, element, times):
    try:
        action = ActionChains(self.browser)
        action.move_to_element(element).perform()
        element.click() 
        for _ in range(times):
            element.send_keys(Keys.SPACE)
            sleep(0.1)
    except Exception as e:
        print 'error scrolling down web element', e

answered Aug 5, 2014 at 21:24

Bob Ezuba

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1 Comment

Andy Over a year ago

thanks this worked for me! If the element is not interactable then you can still send keys using actions.send_keys(Keys.DOWN).perform()

Sitam Jana · Accepted Answer · 2014-07-31 07:07:35Z

0

Use JS to scroll within a web element. One example of such is given below:

def scroll_down_element(self, element):
    try:
        self.browser.execute_script("arguments[0].scrollTop = 200", element)

    except Exception as e:
        print 'error scrolling down web element', e

Hope this helps!

answered Jul 31, 2014 at 7:07

Sitam Jana

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1 Comment

Bob Ezuba Over a year ago

unfortunately, the above code was resulting into an error... I will post the answer below

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