How can i get Strings between double quotes using Regex in Java?
_settext(_textbox(0,_near(_span("My Name"))) ,"Brittas John");
ex: I need My Name and Brittas John
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2 Answers
Get the matched group from index 1 that is captured by enclosing inside the parenthesis (...)
"([^"]*)"
Pattern explanation:
" '"'
( group and capture to \1:
[^"]* any character except: '"' (0 or more times) (Greedy)
) end of \1
" '"'
sample code:
Pattern p = Pattern.compile("\"([^\"]*)\"");
Matcher m = p.matcher("_settext(_textbox(0,_near(_span(\"My Name\"))) ,\"Brittas John\");");
while (m.find()) {
System.out.println(m.group(1));
}
Comments
Try this regex..
public static void main(String[] args) {
String s = "_settext(_textbox(0,_near(_span(\"My Name\"))) ,\"Brittas John\");";
Pattern p = Pattern.compile("\"(.*?)\"");
Matcher m = p.matcher(s);
while (m.find()) {
System.out.println(m.group(1));
}
}
O/P :
My Name
Brittas John
9 Comments
Braj
but it's slow in performance as suggested by me. Look at regex101 - regex debugger for no of steps. I am not sure that is it giving true result.
Cruncher
@user3218114 how is the performance any slower? In both cases the parser should stop as soon as it sees a
".Braj
Look at the no of steps needed to extract the desired result. What is the difference between greedy and lazy pattern? which is faster?
Cruncher
@user3218114 lazy is actually generally faster. It knows exactly when to stop. In this specific case, your greedy should perform equally though. But I still fail to see why it would be any faster.
Braj
@Cruncher look at the demo that I shared you and click on regex debugger link then inspect the steps needed to extract the desired result. Expend all steps.
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