How to assign an object array by index? (C++)

Question

Here is the constructor from my Character class :

Character(int, int, int, string, string, string, string, string, double, double, bool, bool);

And in the main function, here is how I have tried :

Character character[100];
character[0] = {777, 10, 5, "one", "type", "desc", "status", "knife", 10.0, 20.0, false, true};
character[1] = {707, 5, 10, "two", "type2", "desc2", "status", "knife", 15.0, 23.4, true, true};

The error state that it has no storage class or type specifier..

EDIT* Finally got it right using this : p/s - Please provide a better solution if any. =/

Character character[100] = { character[0] = { 777, 10, 5, "one", "type", "desc", "status", "knife", 10.0, 20.0, false, true },
                             character[1] = { 707, 5, 10, "two", "type2", "desc2", "status", "gun", 15.0, 23.4, true, true },
                             character[2] = { 888, 7, 43, "three", "type3", "desc3", "status", "sword", 15.0, 23.4, false, false } };

I would have absolutely no idea what to pass into that constructor without looking. That's a really bad sign. — Qaz
– Qaz, Commented Aug 1, 2014 at 13:33
Looks like you have a forward-declaration, but haven't included the actual header containing the class definition. — jweyrich
– jweyrich, Commented Aug 1, 2014 at 13:33

jweyrich · Accepted Answer · 2014-08-01 13:41:46Z

2

Assuming you have operator= properly defined, you can do this:

Character character[100];
character[0] = Character( 777, 10, 5, "one", "type", "desc", "status", "knife", 10.0, 20.0, false, true );
character[1] = Character( 707, 5, 10, "two", "type2", "desc2", "status", "knife", 15.0, 23.4, true, true );

edited Aug 1, 2014 at 13:41

jweyrich

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answered Aug 1, 2014 at 13:39

dohashi

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4 Comments

Student Over a year ago

What about this? Is it the same?

Character character[100] = {character[0] = { 777, 10, 5, "one", "type", "desc", "status", "knife", 10.0, 20.0, false, true }, 							character[1] = { 707, 5, 10, "two", "type2", "desc2", "status", "gun", 15.0, 23.4, true, true }, 							character[2] = { 888, 7, 43, "three", "type3", "desc3", "status", "sword", 15.0, 23.4, false, false}};

Student Over a year ago

Tried your method. Not working. Still having errors. Image LINK

dohashi Over a year ago

Do you have a constructor for Character that takes no arguments? You'll need that to declare the array. If you don't want to do that, I'd suggest using a vector. Also, showing the actual error message would be helpful.

Student Over a year ago

Yes I have the no argument constructor.

dragosht · Accepted Answer · 2014-08-01 14:21:49Z

1

If you only mean to selectively initialize the elements in the array, C99 has designated initializers which also seem to work in C++.

Character character[100] = {
    [0] = Character( 777, 10, 5, "one", "type", "desc", "status", "knife", 10.0, 20.0, false, true ),
    [1] = Character( 707, 5, 10, "two", "type2", "desc2", "status", "knife", 15.0, 23.4, true, true )
};

You must also have a default Character constructor for the rest of the elements.

However this feature seems to not exist in C++11 but gcc seems to handle it though (probably via an extension).

edited Aug 1, 2014 at 14:21

answered Aug 1, 2014 at 13:56

dragosht

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9 Comments

Student Over a year ago

What is C99? Sorry I'm still new to all this.

dragosht Over a year ago

@Student I was referring to the C99 standard.

Student Over a year ago

Still not working with your method. What wrong am i doing. =/ postimg.org/image/pa57e6adb

dragosht Over a year ago

@Student: I had some misplaced brackets. I reedited my example. Please try again ...

Gall Over a year ago

@dragosht Some compilers allow the use of some C99 features but a warning is clearly displayed. Obviously my comment was about the extension part.

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