I have such code:
function allValid() {
$('input').each(function(index) {
if(something) {
return false;
}
});
return true;
}
which always returns true as return false; affects anonymous inner function. Is there an easy way to call outer function's return?
PS. I am not looking for a workaround, just want to know the answer to original question. If the answer is "not possible" it is fine.
Yeah, store it in a local variable.
function allValid() {
var allGood = true;
$('input').each(function (index) {
if (something) {
allGood = false;
}
});
return allGood;
}
return (allGood = false) inside .each. That will break out of the loop early.
return false inside .each breaks the loop. It's a special case jQuery looks for. github.com/jquery/jquery/blob/master/src/core.js#L537
You could also use Array.prototype.some which iterates until finding an element that matches the criteria.
function allValid() {
var inputs = $('input');
if(inputs.toArray().some(function(input){
if(something)
return true;
})) {
return false;
} else {
return true;
}
}
You can also do this with filter:
var anyInvalid = $('input').filter(function(index) {
if (inValidCheck)
return true;
}).length;
This works because 0 is treated as false, but it actually gives you the number of invalid, which you could use this to display "You have 3 invalid entries" or something if you wanted.
If you want to do this efficiently, I think this is the best way:
function allValid() {
elements = $('input')
for (i = 0; i < elements.length; i++) { invalidityCheck(elements[i]) && return false; }
return true;
}
Edit: Although a more JavaScript-y version would probably use exceptions:
function allValid() {
try
$('input').each(function(index)) {
if (something) { throw 'something happened!'; }
});
catch (e) {
if (e == 'something happened!') {
return false;
} else {
throw e;
}
}
return true;
}
