PHP curl() Response to Associative Array

Question

I have recently started working with the PHP curl() function and I am trying to convert my retrieved JSON object to an associated array. Can anybody point me in the right direction? Thanks!

<?php
$ch = curl_init("https://canvas.instructure.com/api/v1/courses?access_token=7~8SXvaXHjMFZFHAdU5yU0pxNmVwAj40sjW7jRHw1Bvzq09QTFWrJRFxTu4pHAqSZU");
curl_exec($ch);
curl_close($ch);
?>

The response:

[{"account_id":81259,"course_code":"CS50","default_view":"feed","id":870674,"name":"CS50","start_at":"2014-08-05T18:29:18Z","end_at":null,"public_syllabus":false,"storage_quota_mb":250,"apply_assignment_group_weights":false,"calendar":{"ics":"https://canvas.instructure.com/feeds/calendars/course_6QRRvAKDngrrXtTBhzCA5Oz46g3aLgfRt7PNH0NN.ics"},"enrollments":[{"type":"student","role":"StudentEnrollment","enrollment_state":"active"}],"hide_final_grades":false,"workflow_state":"available"}]

php.net/manual/en/function.json-decode.php

ceejayoz
– ceejayoz

2014-08-11 18:18:43 +00:00
Commented Aug 11, 2014 at 18:18 — ceejayoz
– ceejayoz, Commented Aug 11, 2014 at 18:18

Jeff Lambert · Accepted Answer · 2014-08-11 18:24:04Z

1

Use CURLOPT_RETURNTRANSFER to capture the result in a string, which is what you pass to json_encode. I think you're passing $ch to json_decode which is not what you want. (As the error message states, $ch is a resource and json_decode expects to be passed a string).

$ch = curl_init("https://canvas.instructure.com/api/v1/courses?access_token=7~8SXvaXHjMFZFHAdU5yU0pxNmVwAj40sjW7jRHw1Bvzq09QTFWrJRFxTu4pHAqSZU");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
// ...
$response = curl_exec($ch);

// $response will be false if the curl call failed
if($response) {
    var_dump(json_decode($response, true));
}

See curl_setopt documentation for more information.

answered Aug 11, 2014 at 18:24

Jeff Lambert

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2 Comments

Nicolas Over a year ago

Awesome! How come this doesn't print out though?

if($response) {     $array = var_dump(json_decode($response, true));     echo "@@@@@@@@@@@@@@";     echo $array[0]['account_id']; }

Jeff Lambert Over a year ago

if you're assigning the return results of json_decode, remove the var_dump. I only put that in for illustration purposes.

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