Convert matrix to cell array of cell arrays

Question

I want to change a matrix N*123456 to a cells of cells, each sub-cell contains a N*L matrix

Eg:

matrixSize= 50*123456
N=50
L=100

Output will be 1*1235 cell and each cell has a 50*L matrix (last cell has only 50*56)

I know there is a function mat2cell in matlab:

Output = mat2cell(x, [50], [100,100,100,......56])

But it doesn't sound an intuitive solution.

So is there a good solution?

Your example matrix sizes are inconsistent. I don't see how the output can be achieved that way with your example parameters. Also, what exactly is a "cell trunk"? — rayryeng
– rayryeng, Commented Aug 12, 2014 at 4:07

bla · Accepted Answer · 2014-08-12 20:52:42Z

4

If I understand you correctly, assuming your matrix is denoted m, this is what you wanted:

a=num2cell(reshape(m(:,1:size(m,2)-mod(size(m,2),L)),N*L,[]),1);
a=cellfun(@(n) reshape(n,N,L), a,'UniformOutput',false);
a{end+1}=m(:,end-mod(size(m,2),L)+1:end);

(this can be shortened to a single line if you wish)... Lets test with some minimal numbers:

m=rand(50,334);
N=50; 
L=100;

yields:

a = 
[50x100 double]    [50x100 double]    [50x100 double]    [50x34 double]

note that I didn't check for the exact dimension in the reshape, so you may need to reshape to ...,[],N*L) etc.

edited Aug 12, 2014 at 20:52

answered Aug 12, 2014 at 6:12

bla

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2 Comments

bla Over a year ago

for the sake of completeness this is the one line solution:

a=[cellfun(@(n) reshape(n,N,L), num2cell(reshape(m(:,1:size(m,2)-mod(size(m,2),L)),N*L,[]),1),'un',0) ,{m(:,end-mod(size(m,2),L)+1:end)}];

rayryeng Over a year ago

+1 - You took a rather incomprehensible question and clarified with your answer. Very cool!

Yvon · Accepted Answer · 2014-08-13 07:50:15Z

2

Just use elementary maths.

q = floor(123456/100);
r = rem(123456,100);
Output = mat2cell(x, 50, [repmat(100,1,q),r])

answered Aug 13, 2014 at 7:50

Yvon

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