15

I have below XML to parse using XPath:

<?xml version="1.0" encoding="UTF-8"?>
<schema>
  <element name="name_ele1" id="name_id_1" >test name1</element>
  <element name="name_ele2" id="name_id_2" >test name2</element>
  <element name="name_ele2" id="name_id_3" >test name3</element>
</schema>

I want to fetch "name" from the xml document based upon the Id I have passed but I am not able to get the required data instead query is returning blank.

XPathExpression expr = xpath.compile("/schema/element[@id='name_id_2']/name/text()");
1
  • You're using XPath, not XQuery. Java doesn't support XQuery out of the box. Commented Aug 12, 2014 at 9:31

2 Answers 2

31

Like this:

XPathExpression expr = xpath.compile("/schema/element[@id='name_id_2']/@name");

Your expression attempts to select the text inside the name element, instead of the value of the name attribute.

Sign up to request clarification or add additional context in comments.

1 Comment

thank you the following expression solved the mentioned problem
2
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpressionException;
import javax.xml.xpath.XPathFactory;

import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.xml.sax.SAXException;

public class XMLXpathReadder {

    public static void main(String[] args) throws SAXException, IOException, ParserConfigurationException, XPathExpressionException {



         DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
            DocumentBuilder db = dbf.newDocumentBuilder();
            Document document = db.parse(new FileInputStream(new File("C:\\Test.xml")));// same xml comments as above.

            XPathFactory xpf = XPathFactory.newInstance();
            XPath xpath = xpf.newXPath();
            Element userElement = (Element) xpath.evaluate("/schema/element", document,
                XPathConstants.NODE);
            System.out.println(userElement.getAttribute("id"));
            System.out.println(userElement.getAttribute("name"));

    }

}

Above Code work for me.

But how to read values of all elements. I am getting always first elements node only.

<?xml version="1.0" encoding="UTF-8"?>
<schema>
  <element name="name_ele1" id="_1" >test name1</element>
  <element name="name_ele2" id="_2" >test name2</element>
  <element name="name_ele2" id="_3" >test name3</element>
</schema>

1 Comment

Instead of XPathConstants.NODE, try with XPathConstants.NODESET Object result = expr.evaluate(doc, XPathConstants.NODESET); NodeList nodes = (NodeList) result; for (int i = 0; i < nodes.getLength(); i++) { System.out.println(nodes.item(i).getNodeValue()); } . Please check this link: howtodoinjava.com/xml/java-xpath-tutorial-example

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.