check element of one array in another array

Question

I have 3 arrays, I want to check if any element of subarray in mainArray is exist - then it should return true.

I have tried this, but it is returning true only if mainArray containing all the item of sub array.

MY js:

var sub1 = ["0", "10"];
var sub2 = ["18", "3", "13", "4"];
var mainArr = ["0", "1", "5", "8", "9", "10"];
if (containsChk(sub1, mainArr)) {
    alert('yes');
} else {
    alert('no');
}

function containsChk(sub, main) {
    for (var i = 0, len = sub.length; i < len; i++) {
        if ($.inArray(sub[i], main) == -1) return false;
    }
    return true;
}

Jsfiddle

Turn it around, return true if it IS in array and return false after the for loop. — TheFrozenOne
– TheFrozenOne, Commented Aug 12, 2014 at 9:33

Yabada · Accepted Answer · 2014-08-12 09:33:59Z

5

You should just use array.indexOf() (http://www.w3schools.com/jsref/jsref_indexof_array.asp).

for (var i = 0; i < sub1.length; i++)
   if (mainArray.indexOf(sub1[i]) != -1)
      return true;
return false;

answered Aug 12, 2014 at 9:33

Yabada

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Comments

Balachandran · Accepted Answer · 2014-08-12 09:43:10Z

0

try

  var sub1 = ["0", "10"];
var sub2 = ["18", "3", "13", "4"];
var mainArr = ["0", "1", "5", "8", "9", "10"];
if (containsChk(sub1, sub2, mainArr)) {
    alert('yes');
} else {
    alert('no');
}


function containsChk(sub, sub2, main) {
    var isIn = false;
    for (var i = 0, len = sub.length; i < len; i++) {
        if ($.inArray(sub[i], main) != -1) {
            isIn = true;
            break;
        }
    }
    if (!isIn) {
        for (var i = 0, len = sub2.length; i < len; i++) {
            if ($.inArray(sub2[i], main) != -1) {
                 isIn = true;
                 break;
            }
        }
    }


    return isIn;
}

DEMO

answered Aug 12, 2014 at 9:43

Balachandran

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1 Comment

Amit Kumar Over a year ago

it is too complicated. check below answer.

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