I have the following string:
var fileName = $(this).val();
this will give me a result:
C:\fakepath\audio_recording_47.wav
what I want is to obtain : audio_recording_47.wav so, I need to trim it but I don't know how using javascript please help
5 Answers
filename.split('\\').reverse()[0];
This will split the path by slashes, to obtain each part. Then to keep it simple, i reverse the array, so the last part that you need is now the first; and get the first part.
Or, even more simply: filename.split('\\').pop(), which will get the last item from the array.
3 Comments
Frédéric Hamidi
Or you could use
pop(), which would save you the cost of reversing the array. Or you could use lastIndexOf() and substr(), which would save you the cost of building an array in the first place.
Toothbrush
This won't split a UNIX-style path. You can also
split with a regular expression, so it could be this: filename.split(/[\\\/]/g).pop().
Scimonster
@toothbrush For a UNIX path, just replace the \\ with a /.
You could write a little function to return the base name of the path:
function basename(fn) {
var x = fn.lastIndexOf("\\");
if (x >= 0) return fn.substr(x + 1);
return fn;
}
var filename = basename($(this).val());
Comments
You can do like this:
var fileName = $(this).val();
var path = fileName.split('\\');
var lastValue = path[path.length-1];
console.log(lastValue);//audio_recording_47.wav
Or, the shorter way you can do like this:
var fileName = $(this).val();
var path = fileName.split('\\').slice(-1);//audio_recording_47.wav
answered Aug 13, 2014 at 10:14
Bhojendra Rauniyar
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Comments
This should do it:
var trimmedFileName = fileName.match(/[^\\]*$/);
It matches everything that isn't a \ until the end of the string.
1 Comment
Toothbrush
Your regular expression is incorrect.
$ marks the end of the string, but ^ marks the beginning of the string.You could use a regular expression, like this:
var fileName = this.value.replace(/(?:[^\\\/]*[\\\/])*/, '');
Also, there is no need to use that snippet of jQuery, as this.value is both faster and simpler.
Get file name from full path