Python - Issues with selenium button click using XPath

Question

I'm using the following code to click a button on a page but the XPath keeps changing so the code keeps breaking:

mydriver.find_element_by_xpath("html/body/div[2]/div[3]/div[1]/div/div[2]/div[2]/div[4]/div/form[2]/span/span/input").click()

Is there a better way I should be doing this? Here is the code for the button I am trying to click:

<input class="a-button-input" type="submit" title="Button 2" name="submit.button2-click.x" value="Button 2 Click"/>

Ehsan88 · Accepted Answer · 2014-08-18 01:59:26Z

1

XPath is really intelligent. You could do a much more simple search for that:

mydriver.find_element_by_xpath("//input[@name='submit.button2-click.x']")

which tells: search all input elements whose name equals to 'submit.button2-click.x' which will be the element of your choice.

Don't forget to try Firefix XPath Checker add-on before going to code.

answered Aug 18, 2014 at 1:59

Ehsan88

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Comments

bcar · Accepted Answer · 2014-08-18 01:42:22Z

1

I'd use findelement(by.name(" submit.button2-click.x")).click() or use find element(by.cssSelector("selector ")).click()

answered Aug 18, 2014 at 1:42

bcar

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Thanks for the reply. This also works mydriver.find_element_by_name("submit.button2-click.x").click()