numpy: bitwise and on array

Question

I'm trying to do an "&" operation across all the values in a simple bool array. The array I have is as follows:

array([False False True], dtype=bool)

The only thing I've come up with is to slice out the values in the array and use "&" to give a "False" result. I feel like there must be a better way but I don't know enough about numpy to use it properly.

Just FYI, this operation is not bitwise in memory, but rather bytewise, since boolean variables take up a full byte each :/. You can do true bitwise operations on e.g. np.uint8 variables however using the operators &, |, <<, >> if necessary. — eickenberg
– eickenberg, Commented Aug 19, 2014 at 6:12

shx2 · Accepted Answer · 2014-08-19 05:20:02Z

2

Use arr.all(), which is the same as np.all(arr):

import numpy as np
arr = np.array([False, False, True], dtype=bool) 
arr.all()
=> False
np.all(arr)
=> False

answered Aug 19, 2014 at 5:20

shx2

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1 Comment

eickenberg Over a year ago

For completeness, the converse of np.all is np.any.

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