Using $.get [AJAX] to pass a JS variable to PHP not working

Question

I am trying to pass a variable from javascript to PHP using a an AJAX request [$.get] but am getting nothing through the $_GET method. I am wondering why the variable email won't pass even though there is a value within it.

fetch.js

email = resp.emails[i].value; 
$url = 'login.php'; //this file is on the same directory as fetch.js
//AJAX
$.get($url, {name: email});

login.php

$googleid = $_GET['name'];
echo $googleid; //nothing showing

If you need any more details please don't hesitate to ask.

EDIT I know I am going to get flamed for this but this was a typo. In my script I didn't make this mistake.

You send GET variable named name. So in php you can access it by $_GET['name'], not $_GET['email'] — hindmost
– hindmost, Commented Aug 19, 2014 at 15:25
Also, login.php should be in the same directory as your HTML file, not necessarily the JS file. Are you getting a 404 when calling $.get ? Check your dev console. Try $.get($url, {name: email}).fail(function() {alert("An error happened")}) — Ruan Mendes
– Ruan Mendes, Commented Aug 19, 2014 at 15:37
Did you try the fail method I suggested? Also, where are you trying to use the value that AJAX gives you? Show that code, what you have shown doesn't even have a callback for $.get — Ruan Mendes
– Ruan Mendes, Commented Aug 19, 2014 at 15:44

MH2K9 · Accepted Answer · 2014-08-19 15:36:00Z

2

 $googleid = $_GET['email'];

should be

 $googleid = $_GET['name'];

Because your GET variable was name and email was value that assign to name (eg, name = [email protected]). So you should access it by $_GET['name']

edited Aug 19, 2014 at 15:36

answered Aug 19, 2014 at 15:26

MH2K9

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1 Comment

Ruan Mendes Over a year ago

Consider deleting this answer now that the OP updated their question, it was a typo

user32342534 · Accepted Answer · 2014-08-19 15:27:06Z

1

It should be

$_GET['name'];

What is the line email = resp.emails[i].value;? Has that a value?

answered Aug 19, 2014 at 15:27

user32342534

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hindmost · Accepted Answer · 2014-08-19 15:29:09Z

1

Since in JS you send GET variable named name then in PHP you have to access it by $_GET['name'], not $_GET['email']:

$googleid = $_GET['name'];

answered Aug 19, 2014 at 15:29

hindmost

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Steini · Accepted Answer · 2014-08-19 15:26:23Z

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You have to use $_POST for a parameter request.

For get the parameter would be visible in the url what you probably dont want like [email protected]

answered Aug 19, 2014 at 15:26

Steini

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2 Comments

Apparently Im user2212428 Over a year ago

I'l have to change $.get(method) to something else. Will I?

Steini Over a year ago

no you have to use $_POST[] instead of $_GET[] in your PHP script.

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