php: If url contains one of the array value then X [closed]

Question

Closed. This question needs to be more focused. It is not currently accepting answers.

Want to improve this question? Guide the asker to update the question so it focuses on a single, specific problem. Narrowing the question will help others answer the question concisely. You may edit the question if you feel you can improve it yourself. If edited, the question will be reviewed and might be reopened.

Closed 11 years ago.

Improve this question

I will re-explain the whole situation as it got confused. And keep in mind i do not know much about coding. I have an array like that:

<?php
$mytestarray = array(
'test1'=>'aaa',
'test2'=>'aaa',
'test3'=>'ccc'
);

Now what i need is to check if the array keys exist in the current url of the webpage. If they exist i will do something if not the rest of the code will go on loading (this code will place in the header of my website). So there are many codes to run if this statement returns false.

So in the array example above http://localhost/test1xxx.php should return True as the url contains test1 which is the first array key http://localhost/test2asdasdasdas.php should also return True.

That is it. I do not need anything more or less or different. As the array values will be used somewhere else, the script should check if array keys exists or not in the url

hello sorry but i dont know much about coding. So those do not answer my question as am trying to check if the URL contains this — Karl Heinz
– Karl Heinz, Commented Aug 19, 2014 at 18:46
I don't think his problem was to loop/search through the array, but rather than find a string representation or index representation of the current requested URI. — Zander Rootman
– Zander Rootman, Commented Aug 19, 2014 at 18:46
just noticed this code works when it is executed on aaa.php however what i need is the left side of the array. so test1. — Karl Heinz
– Karl Heinz, Commented Aug 19, 2014 at 19:55

Zander Rootman · Accepted Answer · 2014-08-19 21:01:30Z

4

EDIT
Improved answer for user.

<?php
$mytestarray = array(
"test1"=>'aaa',
"test2"=>'bbb',
"test3"=>'ccc'
);
// Create a function so it's cooler
function in_URI(array $array)
{
    // Please review the code entirely.
    foreach($array AS $key => $value){
        // If the URI does contain one of the words in the array
        if (strpos($_SERVER['REQUEST_URI'], $key) !== FALSE) {
            // Return that it has been found
            return true;
        }
    }
    // Return that the values have not been found
    return false;
}

if(in_URI($mytestarray)){

    echo "YAAAY! It's in here!";

}else{

    echo "Awwww :(";
}

edited Aug 19, 2014 at 21:01

answered Aug 19, 2014 at 18:45

Zander Rootman

2,2082 gold badges19 silver badges29 bronze badges

Sign up to request clarification or add additional context in comments.

9 Comments

Karl Heinz Over a year ago

thanks but i could not get it work. I need something like. if the current url contains one of the array text then do this. IF does not contain the rest of the code will work

Zander Rootman Over a year ago

How did you try to implement it? And what do you mean it doesn't work? Did you get any errors?

Karl Heinz Over a year ago

I am trying to put it into the header of my website. So if someone enters to an url directly which contains a text from my array i will show him an empty page. So this code will load in all of the pages in my website. So the page should go on loading if the person does not get filtered through this code

Zander Rootman Over a year ago

See the edited answer, and let me know if that was what you're looking for.

Karl Heinz Over a year ago

i could not get it work. i posted what i did. something is not right

|

Collectives™ on Stack Overflow

php: If url contains one of the array value then X [closed]

1 Answer 1

9 Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

9 Comments

Linked

Related