I am trying to figure out how to get a variable name I have assigned to a method, for example:
import inspect
def a():
print inspect.stack()[0][3]
b = a
b()
This will return a instead of b, and if I use [1][3] for the indices, it will give me <module>. I am expecting to get b. Is there any simple pythonic solution for this? Do i have to create decorators and wrappers only to get this?.
There is no (easy) way to do so.
That is getting put into the stack frame is not the name the function is called with, but the name which is written in the code object of the function a.func_code.co_name.
There is no way to detect how a function is called. You could try to inspect the code one level above:
With the function changed to
def a():
return inspect.stack()
we can see
>>> import dis
>>> f=a()[1][0]
>>> dis.dis(f.f_code)
1 0 LOAD_NAME 0 (a)
3 CALL_FUNCTION 0
6 LOAD_CONST 0 (1)
9 BINARY_SUBSCR
10 LOAD_CONST 1 (0)
13 BINARY_SUBSCR
14 STORE_NAME 1 (f)
17 LOAD_CONST 2 (None)
20 RETURN_VALUE
>>> b=a
>>> f=b()[1][0]
>>> dis.dis(f.f_code)
1 0 LOAD_NAME 0 (b)
3 CALL_FUNCTION 0
6 LOAD_CONST 0 (1)
9 BINARY_SUBSCR
10 LOAD_CONST 1 (0)
13 BINARY_SUBSCR
14 STORE_NAME 1 (f)
17 LOAD_CONST 2 (None)
20 RETURN_VALUE
>>> f=[b][0]()[1][0]
>>> dis.dis(f.f_code)
1 0 LOAD_NAME 0 (b)
3 BUILD_LIST 1
6 LOAD_CONST 0 (0)
9 BINARY_SUBSCR
10 CALL_FUNCTION 0
13 LOAD_CONST 1 (1)
16 BINARY_SUBSCR
17 LOAD_CONST 0 (0)
20 BINARY_SUBSCR
21 STORE_NAME 1 (f)
24 LOAD_CONST 2 (None)
27 RETURN_VALUE
It would be hard to parse this reliably.
