regular expression over multiple lines python

Question

I have a String Alltext that contains text across multiple lines

aaaaa    
D0  
aaaaa

text0...........


aaaaa                                      
D1  
aaaaa  
text 1 ..........


aaaaa  
D2  
aaaaa  
text 2

I want to keep just the text part i.e. text0...., text1 , text2.... and remove the indicators

aaaaa
D0
aaaaa, 

aaaaa
D1
aaaaa

and so on.These indicate next text segment. I tried this regular expression

re.sub("[a]* \sD[0-9]*\\s[a] * ", " ",Alltext)

but this just removes D0, D1 and not the aaaa The output I get

aaaaa  
aaaaa   
text0  
aaaaa       
aaaaa  
text1

How can I remove these aaaaa

Avinash Raj · Accepted Answer · 2014-08-25 08:03:38Z

1

You don't need to put a single character inside character class and also you don't need to double escape \s

a*\s*D[0-9]*\s*a*\s*

DEMO

Python code would be,

>>> import re
>>> s = """aaaaa    
D0  
aaaaa

text0...........


aaaaa                                      
D1  
aaaaa  
text 1 ..........


aaaaa  
D2  
aaaaa  
text 2  """
>>> m = re.sub(r'a*\s*D[0-9]*\s*a*\s*', r'', s)
>>> m
'text0...........\n\n\ntext 1 ..........\n\n\ntext 2  '
>>> print m
text0...........


text 1 ..........


text 2

edited Aug 25, 2014 at 8:03

answered Aug 25, 2014 at 7:48

Avinash Raj

175k32 gold badges247 silver badges289 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

vks · Accepted Answer · 2014-08-25 09:13:56Z

1

 print re.findall(r"^text.*$",x,re.M)

Simle findall should do this as well.

answered Aug 25, 2014 at 9:13

vks

68.1k11 gold badges96 silver badges132 bronze badges

Collectives™ on Stack Overflow

regular expression over multiple lines python

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related