How to use '+' to concat string in JSON data?

Question

I've a code like this:

jQuery.each(images, function (k, v) {
    v = v.split(':');

    data.questions.push({
        source: questionAssetPath + v[0],
        match: v[1],
        mouse: mouseAssetPath + v[2] + '.png'
    });

    data.answers.push({
        answer: v[1],
        match: v[1]
    });
});

When I run a grunt task (browserify:js), I've got this error:

ParseError: Unexpected token +

Please help me figure out of this.

Thanks you.

UPDATE: I've solved it myself. Thanks guys. I've noticed that I can't use + operator with objects (wtf with me)

images = [
    "maria-ozawa.png:MariaOzawa:1",
    "aoi-125239.png:Aoi:2",
    "sasha-grey.png:SashaGrey:3"
];

jQuery.each(images, function (k, v) {
    v = v.split(':');
    v[0] = questionAssetPath + v[0];
    v[2] = mouseAssetPath + v[2] + '.png';
    data.questions.push({source: v[0], match: v[1], mouse: v[2]});
    data.answers.push({answer: v[1], match: v[1]});
});

Why not concatenate it in the variable before you build the JSON? — ydaetskcoR
– ydaetskcoR, Commented Aug 25, 2014 at 8:42
Seems that you have character + in your JSON, so provide JSON example where this error is happened. — Eugene Obrezkov
– Eugene Obrezkov, Commented Aug 25, 2014 at 8:44
I don't see any problem with this code. Maybe the problem comes from your data. — Binary Brain
– Binary Brain, Commented Aug 25, 2014 at 8:45

Abdul Jabbar · Accepted Answer · 2014-08-25 08:51:35Z

1

 Query.each(images, function (k, v) {
        v = v.split(':');
        questionAssetPath = questionAssetPath.concat(v[0])
        data.questions.push({source: questionAssetPath, match: v[1], mouse: mouseAssetPath + v[2] + '.png'});
        data.answers.push({answer: v[1], match: v[1]});
    });

That will get rid of the need of using '+' and will solve the error

See the JavaScript String concat() Method

edited Aug 25, 2014 at 8:51

answered Aug 25, 2014 at 8:45

Abdul Jabbar

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Comments

Amir Popovich · Accepted Answer · 2014-08-25 08:48:28Z

0

Check your data because this seems to work fine:

JSFIDDLE

var images = ["a:b:c","d:e:f"];
var data = {
    questions:[], 
    answers:[]   
};
var questionAssetPath = "c:\\abc\\";
var mouseAssetPath = "c:\\def\\";

$.each(images, function (k, v) {
    v = v.split(':');
    data.questions.push({source: questionAssetPath + v[0], match: v[1], mouse: mouseAssetPath + v[2] + '.png'});
    data.answers.push({answer: v[1], match: v[1]});
});

console.log(data);

answered Aug 25, 2014 at 8:48

Amir Popovich

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