Pass input value to ajax get Laravel

Question

I am fairly new to Laravel and ajax in general, what I am trying to implement is to pass the value of an input field through an ajax get request. My request looks like this:

function getInfo() {

        $.ajax({
            url: "info",
            dataType: "json"
        }).success(function(data){
            $('#result').append(JSON.stringify(data));
        }).fail(function(){alert('Unable to fetch data!');;
        });
    }
    $('#infoSubmit').click(getInfo);

I have setup a route for my function in laravel that works like this public/info/Variable <--

When I add a variable after info/ I get the data for that variable (e.g profile name)

I need to pass this variable from an inputfield to ajax request to something like this: url: "info/+$inputfieldVariable"

PeterKA · Accepted Answer · 2014-08-25 13:50:13Z

1

Change:

url: "info",

TO:

url: "info/" + $('input-field-selector').val(),

Not sure about the correctness of your JS code: Shouldn't you be using done instead of success?

edited Aug 25, 2014 at 13:50

answered Aug 25, 2014 at 13:44

PeterKA

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1 Comment

user3127632 Over a year ago

forgot to remove it , i didn't had "fail" before it. I would revise it and use done instead

Oliboy50 · Accepted Answer · 2014-08-25 13:50:27Z

0

JavaScript:

function getInfo() {

    var myFieldsValue = {};
    var $inputs = $("#myForm :input");
    $inputs.each(function() {
        myFieldsValue[this.name] = $(this).val();
    });

    $.ajax({
        url: "info",
        dataType: "json",
        data: myFieldsValue,
        type: "GET" // Even if its the default value... looks clearer
        success: function(data){
            $('#result').append(JSON.stringify(data));
        },
        error: function(){
            alert('Unable to fetch data!');
        }
    });

    return false;
}
$('#infoSubmit').click(getInfo);

Untested but should be something like that

answered Aug 25, 2014 at 13:50

Oliboy50

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