Go Lang Print Inputted Array

Question

I am studying Go lang right now and I encountered a problem when trying to print inputted Array. My code is like this:

package main

import (
    "fmt"
)

func main() {
    var n int
    fmt.Scan(&n)
    set(n)
}

func set(n int) {
    a := make([]int, n)
    for i := 0; i < n; i++ {
        fmt.Scan(&a[i])
    }
    for y := 0; y < n; y++ {
        fmt.Println(a[y])
    }
    return
}

my problem is when Inputted a number as a size for the array, that number always get printed too. Like when I inputted 8 as the array size then followed by the array value for example 10 9 8 7 6 5 4 3 then I get the wrong output: 8 10 9 8 7 6 5 4.Iit should be 10 9 8 7 6 5 4 3.

I don't see anything wrong. Try just printing the whole array at once. — Mr_Pink
– Mr_Pink, Commented Aug 26, 2014 at 16:46
I can't reproduce that, what version of Go are You using? and what OS? — OneOfOne
– OneOfOne, Commented Aug 26, 2014 at 16:47
@Exill: For the Go version and OS, post the output of the go version command. — peterSO
– peterSO, Commented Aug 26, 2014 at 17:10

Gupta · Accepted Answer · 2015-12-26 06:54:28Z

3

package main
import ("fmt")
func main() {
  var n int
  fmt.Scan(&n)
  set(n)
}

func set(n int) {
  a := make([]int, n)
  for i := 0; i < n; i++ {
      fmt.Scan(&a[i])
    }
  fmt.Println(a)
 }

edited Dec 26, 2015 at 6:54

Gupta

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answered Dec 26, 2015 at 5:33

Faisal

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1 Comment

prasun Over a year ago

please add some description - over code only answer

dyoo · Accepted Answer · 2014-08-29 06:41:25Z

1

Can not duplicate problem yet. For example:

package main

import (
    "bytes"
    "fmt"
    "io"
)

func main() {
    var n int
    sampleInput := bytes.NewBufferString("3 1 2 3")
    fmt.Fscan(sampleInput, &n)
    set(sampleInput, n)
}

func set(input io.Reader, n int) {
    a := make([]int, n)
    for i := 0; i < n; i++ {
        fmt.Fscan(input, &a[i])
    }
    for y := 0; y < n; y++ {
        fmt.Println(a[y])
    }
    return
}

is a variation of your program. It has the expected behavior: it prints the numbers 1 2 3 that it read into the slice.

answered Aug 29, 2014 at 6:41

dyoo

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Comments

jinugeorge · Accepted Answer · 2018-08-10 07:56:53Z

0

i:=0
var a[5] int
for(i<5){
fmt.Print("Enter Input")
var input int
fmt.Scanf("%d",&input)
a[i]=input
i+=1
}
fmt.Print(a)

This seems to work for me.Please refer.

answered Aug 10, 2018 at 7:56

jinugeorge

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