When I was trying to parse date in Java, both of these line return PhaseException, double-checked and doesn't know what' going on, please help!
Date dateobj = new SimpleDateFormat("MMM dd, yyyy").parse("Nov 12, 1994");
Date timeobj = new SimpleDateFormat("hh:mm a").parse("8:20 pm");
The full trace:
java.text.ParseException: Unparseable date: "Nov 12, 1994"
at java.text.DateFormat.parse(Unknown Source)
at testTime.main(testTime.java:12)
First thing you code doesnot produces any Exception but still it is always safe to specify the Locale
Like this
Date dateobj = new SimpleDateFormat("MMM dd, yyyy", Locale.ENGLISH)
.parse("Nov 12, 1994");
Date timeobj = new SimpleDateFormat("hh:mm a", Locale.ENGLISH)
.parse("8:20 pm");
Double check the declared throws for DateFormat#parse. It is throwing what's known as a checked exception; this means that even though this exception occurs, you should be able to recover from it.
You must either:
throws ParseException at the signature of your method), orWrap the expression in a try...catch block. An example is below.
Date dateobj = null;
Date timeobj = null;
try {
dateobj = new SimpleDateFormat("MMM dd, yyyy").parse("Nov 12, 1994");
timeobj = new SimpleDateFormat("hh:mm a").parse("8:20 PM");
} catch(ParseException e) {
e.printStackTrace();
}
As it stands with your snippet, if I take either precaution (declaring it to be thrown or catch it myself), then I encounter no further runtime errors.
Thanks to JB Nizet, this error is caused by a different locale setting, adding locale to the simpledateformat works
